Question

How do you solve `Ln(x)-2=0`?

Answer 1

`x = e^2`

Explanation:

A logarithm `log_a(x)` is the value fulfilling the equation `a^(log_a(x))=x`.

`ln` represents the natural logarithm, that is, the logarithm with base `e`. To solve, then, we can isolate `ln(x)` and then apply the exponential function. As `ln(x)` is the same as `log_e(x)`, then `e^ln(x) = x`.

`ln(x) - 2 = 0`

`=>ln(x) = 2`

`=>e^(ln(x))= e^2`

`=> x = e^2`