# How do you solve ln2x=4?

$x = \frac{{e}^{4}}{2} \cong 27.3$

#### Explanation:

$\ln \left(2 x\right) = 4$
We can take both sides and put them as exponents of $e$. On the left side, this is taking one function ($\ln$) and applying the inverse to it ($e$), so the result is that they cancel out and we end up with the term inside the $\ln$:
$2 x = {e}^{4}$
$x = \frac{{e}^{4}}{2} \cong 27.3$