# How do you solve #lnx+ln(2x)=2#?

##### 1 Answer

Aug 6, 2016

#### Explanation:

If

#ln x + ln(2x) = ln (x*2x) = ln(2x^2)#

and

#2 = ln e^2#

So we have:

#ln (2x^2) = ln (e^2)#

Since

#2x^2 = e^2#

So:

#x^2 = e^2/2#

Hence:

#x = e/sqrt(2) = (sqrt(2))/2e#

Note we ignore the negative square root since we are only looking at the case