How do you solve $lnx+ln3x=12$ ?

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Answer 1 · 2016-11-19T07:00:05

$+-e^6/sqrt3=+-232.92$ , nearly

$ln x + ln (3x) = ln (x()(3x))=ln(3x^2)$ . Inversely,

$3x^2=e^12$ . So,

$x=+-sqrt(e^12/3)$

$=+-e^6/sqrt3$ .

How do you solve lnx+ln3x=12lnx+ln3x=12?