Question

How do you solve `log_(1/10)x=-3` and check the solutions?

Answer 1

`x=1000`

Explanation:

We use that

`log_a(b)=n` if `a^n=b`
then we get

`(1/10)^(-3)=x`
`x=1000`
Checking the solution:

`ln(1000)/ln(1/10)=(3ln(10))/ln(10^(-1))=-3`