Question

How do you solve `\log _ { 2} ( 9- 4x ) = 3`?

Answer 1

`x=1/4=0.25`.
See explanation.

Explanation:

You have:
`log_2 (9-4x) =3`

so you can do:
`2^[log_2 (9-4x)] =2^3`

which becomes:
`(9-4x) = 2^3`

and just solve for x:
`4x = 9-8`
i.e.
`x=1/4=0.25`