How do you solve #\log (2x-8)=2#?

1 Answer
Kevin B.
Nov 13, 2016

#x=54#

Explanation:

I'm going to assume the #log# in this question is #log_10#, correct the answer if you are assuming #ln# or #log_e#.

Raise both sides to a base of #10#:

#(2x-8)=10^2#

Solve for #x#:
#2x=100+8#
#x=54#

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