Question

How do you solve `log_3 +log_3 (2x)=log_3 56`?

Answer 1

The operand is missing in the first term. If it is a, the answer is `28/a`.

Explanation:

Assuming that the missing operand in the first term is a,

the equation is

`log_3 a + log 3 (2x) = log_3 56`

So, `log_3 (a X 2x)=log_3 56.`

And so, `2ax=56 and x =28/a`.