# How do you solve log_3 x=2?

$x = 9$

#### Explanation:

We can write log problems two different ways:

${\log}_{a} b = c$

${a}^{c} = b$

So we can take the original question:

${\log}_{3} x = 2$

and rewrite it to:

${3}^{2} = x = 9$