How do you solve #log_3 x-log_3(x-1)=1#? Precalculus Properties of Logarithmic Functions Common Logs 1 Answer Cesareo R. Aug 17, 2016 Answer: #x = 3/2# Explanation: #log_3 x-log_3(x-1)=1 = log_3 3# so #log_3(x/(x-1))=log_3 3# so #x/(x-1) = 3# or #x =3(x-1)# Solving for #x# gives #x = 3/2#. Verifying the feasibility #log_3 (3/2) - log_3(1/2)=log_3 3# So, #x = 3/2# is the solution. Related questions What is the common logarithm of 10? How do I find the common logarithm of a number? What is a common logarithm or common log? What are common mistakes students make with common log? How do I find the common logarithm of 589,000? How do I find the number whose common logarithm is 2.6025? What is the common logarithm of 54.29? What is the value of the common logarithm log 10,000? What is #log_10 10#? How do I work in #log_10# in Excel? See all questions in Common Logs Impact of this question 120 views around the world You can reuse this answer Creative Commons License