# How do you solve log_3x=9?

$x = {3}^{9}$
When I write ${\log}_{a} b = c$, I ask to what power I raise the base $a$ tp get $b$; here ${a}^{c} = b$. By way of example, ${\log}_{10} 100 = 2 ,$ i.e. ${10}^{2} = 100 , {10}^{3} = 1000 e t c .$
Given that ${\log}_{3} x = 9$, then $x = {3}^{9}$, whatever this is it is large!