How do you solve #log_4 5 - log_4x = log_4(5/4)#?

1 Answer
EZ as pi
Oct 6, 2016

#x=4#

Explanation:

#log_4 5 - log_4x = log_4(5/4)#

Condense two log terms into one log term
#rarr# If the logs are being subtracted, the values are being divided.

#log_4(5/x) = log_4(5/4)#

Without any further working, we can see by inspection that

#x=4#

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