How do you solve #\log _ { 4} ( x - 3) = 2#?

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Answer 1 · 2018-05-28T03:18:59

#x=19#

The key realization is that we can leverage the log property

#y=log_a(x)=>x=a^y#

Thus, we can rewrite our logarithm as

#x-3=4^2#

And it's just algebra from this point on. Simplifying the right, we get

#x-3=16#

And lastly, adding #3# to both sides we get

#x=19#

Hope this helps!