How do you solve #\log ( 4n - 9) = \log ( 3n - 2)#?
1 Answer
Mar 14, 2017
Explanation:
Using the
#color(blue)"law of logarithms"#
#color(red)(bar(ul(|color(white)(2/2)color(black)(logx=logyhArrx=y)color(white)(2/2)|)))#
#rArr4n-9=3n-2#
#rArrn=7" is the solution"#
