How do you solve log 5x=log(2x+9)?

Jul 16, 2016

Using the $\textcolor{b l u e}{\text{law of logarithms}}$
$\textcolor{red}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} \textcolor{b l a c k}{\log x = \log y \Rightarrow x = y} \textcolor{w h i t e}{\frac{a}{a}} |}}}$
$\Rightarrow 5 x = 2 x + 9 \Rightarrow 3 x = 9 \Rightarrow x = 3$