# How do you solve #log_6 2x + log_6 (x + 3) = 2# and find any extraneous solutions?

##### 2 Answers

#### Answer:

#### Explanation:

Use

Here,

So, 2x(x+3)=36. solving,

Negative x is inadmissible for

#### Answer:

The Soln. is

#### Explanation:

We use the following **Rules of Logarithm Function** :-

**Defn.**

Given that,

By **Inspection** , **quadr. poly.** , it

must have one more root. To find it, we observe that the **product
of the roots** is

But, **L.H.S. undefined** , and, hence, it is an **Extraneous Soln.**

Thus, the soln. is