# How do you solve #log_6 3x+ log_6 (x-1) =3# and find any extraneous solutions?

##### 1 Answer

May 21, 2016

#### Answer:

x = 9 and the extraneous solution is

#### Explanation:

Inverting,

The roots of this quadratic are

Negative root is inadmissible. So, x = 9.