How do you solve #log_(x-2) (9) =2#? Precalculus Properties of Logarithmic Functions Logarithm-- Inverse of an Exponential Function 1 Answer ali ergin May 6, 2016 #x=5# Explanation: #log_(x-2) 9=2# #log_a b=c" "a^c=b# #9=(x-2)^2# #3^2=(x-2)^2# #3=x-2# #x=3+2# #x=5# Answer link Related questions What is a logarithm? What are common mistakes students make with logarithms? How can a logarithmic equation be solved by graphing? How can I calculate a logarithm without a calculator? How can logarithms be used to solve exponential equations? How do logarithmic functions work? What is the logarithm of a negative number? What is the logarithm of zero? How do I find the logarithm #log_(1/4) 1/64#? How do I find the logarithm #log_(2/3)(8/27)#? See all questions in Logarithm-- Inverse of an Exponential Function Impact of this question 2780 views around the world You can reuse this answer Creative Commons License