# How do you solve #log(x-3)+log(x+5)=log9#?

##### 1 Answer

Jan 4, 2017

#### Answer:

#### Explanation:

#log(x-3)+log(x+5)=log9#

Using

#log(x-3)(x+5)=log9#

Using

#(x-3)(x+5)=9#

# :. x^2+5x-3x-15=9#

# :. x^2+2x-24=0#

# :. (x+6)(x-4)=0#

# :. x=4,-6#

Now depending upon the context of the question we could probably eliminate