Question

How do you solve `(log_x (7)(log_7 (5)) = 6`?

Answer 1

`(log7)/(logx)*(log5)/(log7)=6->log5/logx=6->log_x5=6->x^6=5->x=5^(1/6)=root6(5)`

Explanation:

Use change of base formula`log_bx=logb/logx` to rewrite each logarithm and then simplify then solve for x