How do you solve #log2+logx=1#? Precalculus Properties of Logarithmic Functions Common Logs 1 Answer Alan N. Jul 12, 2016 5 (Assuming #log = log_10#) Explanation: #log_10 2 + log_10 x = 1# Using: #log_n a + log_n b = log_n(ab)# we may rewrite the equation as: #log_10 2x = 1# Using: #log_n a = b -> a = n^b# we may simplify the equation as: #2x = 10^1# #2x = 10# #x = 5# Answer link Related questions What is the common logarithm of 10? How do I find the common logarithm of a number? What is a common logarithm or common log? What are common mistakes students make with common log? How do I find the common logarithm of 589,000? How do I find the number whose common logarithm is 2.6025? What is the common logarithm of 54.29? What is the value of the common logarithm log 10,000? What is #log_10 10#? How do I work in #log_10# in Excel? See all questions in Common Logs Impact of this question 9551 views around the world You can reuse this answer Creative Commons License