How do you solve $logx+log7=log37$ ?

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Answer 1 · 2016-07-22T09:32:56

$x = 37/7 = 5 2/7$

If logs terms are being added, then the numbers are being multiplied.
Write the two added log terms as the log of a single number.

$log(7x) = log37 " If LogA = logB, then A = B"$

$7x =37$

$x = 37/7$

$x = 5 2/7$

How do you solve logx+log7=log37logx+log7=log37?