How do you solve #logx+log7=log37#?

1 Answer
Jul 22, 2016

Answer:

#x = 37/7 = 5 2/7#

Explanation:

If logs terms are being added, then the numbers are being multiplied.
Write the two added log terms as the log of a single number.

#log(7x) = log37 " If LogA = logB, then A = B"#

#7x =37#

#x = 37/7#

#x = 5 2/7#