Question

How do you solve `(m^2 + 2m + 1)/( m^3 + 3m^2 + 3m +1)(m^2/(m - (3m)/3))`?

Answer 1

The function doesn't exist.

Explanation:

`color(white)=(m^2+2m+1)/(m^3+3m^2+3m 1)(m^2/(m-(3m)/3))`

`=(m^2+2m+1)/(m^3+3m^2+3m 1)(m^2/(m-(color(red)cancelcolor(black)3m)/color(red)cancelcolor(black)3))`

`=(m^2+2m+1)/(m^3+3m^2+3m 1)(m^2/(color(red)cancelcolor(black)(m-m)))`

`=(m^2+2m+1)/(m^3+3m^2+3m 1)(m^2/0)`

Since there is division by zero, the function cannot exist.