How do you solve #m^ { 2} + 3= 12#?

2 Answers
kamil9234
Apr 6, 2017

#m=3# OR #m=-3#

Explanation:

#m^2=12-3#
#m^2=9#
#m=sqrt(9)# OR #m=-sqrt(9)#
#m=3# #m=-3#

Jim G.
Apr 6, 2017

#m=+-3#

Explanation:

#"subtract 3 from both sides of the equation"#

#m^2cancel(+3)cancel(-3)=12-3#

#rArrm^2=9#

#"take the "color(blue)"square root of both sides"#

#sqrt(m^2)=+-sqrt9#

#rArrm=+-3#

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