How do you solve #(m+3)/4=(m-5)/7#? Algebra Linear Equations Equations with Ratios and Proportions 1 Answer Tony B Aug 2, 2016 #m=-41/3# Explanation: #color(blue)("Using shortcut methods")# #(m+3)/4=(m-5)/7 larr" Cross multiply giving:"# #color(white)(.)# #7(m+3)=4(m-5) larr" Multiply out the brackets giving:"# #color(white)(.)# #7m+21=4m-20 larr" Collecting like terms giving:"# #7m-4m=-21-20# #3m=-41 larr" divide both sides by 3 giving:"# #color(white)(.)# #color(white)(.)# #m=-41/3# Answer link Related questions What is the difference between proportions and ratios? What is the difference between ratios and rates? What are cross products? How do you write "12 meters to 4 floors" as a rate? How do you write and simplify "150 boys to 175 girls" as a ratio? How do you solve #\frac{6}{19} = \frac{x}{11}#? How do you solve #\frac{n+1}{11} = -2#? How do you solve #\frac{0.1}{1.01} = \frac{1.9}{x}#? How do you use proportions to solve how much money the restaurant made if it serves 250 people... How do you solve #x/4-7=13#? See all questions in Equations with Ratios and Proportions Impact of this question 327 views around the world You can reuse this answer Creative Commons License