How do you solve #(m+3)/4=(m-5)/7#? Algebra Linear Equations Equations with Ratios and Proportions 1 Answer Tony B Aug 2, 2016 Answer: #m=-41/3# Explanation: #color(blue)("Using shortcut methods")# #(m+3)/4=(m-5)/7 larr" Cross multiply giving:"# #color(white)(.)# #7(m+3)=4(m-5) larr" Multiply out the brackets giving:"# #color(white)(.)# #7m+21=4m-20 larr" Collecting like terms giving:"# #7m-4m=-21-20# #3m=-41 larr" divide both sides by 3 giving:"# #color(white)(.)# #color(white)(.)# #m=-41/3# Related questions What is the difference between proportions and ratios? What is the difference between ratios and rates? What are cross products? How do you write "12 meters to 4 floors" as a rate? How do you write and simplify "150 boys to 175 girls" as a ratio? How do you solve #\frac{6}{19} = \frac{x}{11}#? How do you solve #\frac{n+1}{11} = -2#? How do you solve #\frac{0.1}{1.01} = \frac{1.9}{x}#? How do you use proportions to solve how much money the restaurant made if it serves 250 people per ... How do you solve #x/4-7=13#? See all questions in Equations with Ratios and Proportions Impact of this question 220 views around the world You can reuse this answer Creative Commons License