How do you solve #n/(n+1)=3/5#?

2 Answers
Apr 27, 2017

Answer:

Isolate n.

Explanation:

Firstly we can multiply both sides by #n+1#, doing this, we get: #n/(n+1) * n+1 = 3/5 * (n+1) = n#
Now we can multiply both sides by #5#, #n*5 = 3/5*(n+1)*5 -> 5n = 3n + 3#, solving for #n# we get #2n = 3, n = 3/2#

Apr 27, 2017

Answer:

n = #3/2#

Explanation:

First, you have to understand cross multiplying.
5 would cross with n to make 5n
3 would cross with n + 1 to make 3n + 3

The equation would look like 5n = #3n+3#
Bring 3n over to 5n and subtract from both sides.
3n - 3n would cancel out while 5n - 3n would give 2n.

The equation would look like: 2n = 3
Divide 3#divide#2. (Do not be afraid of fractions)

#n=3/2#