How do you solve p^ { 2} - 35= 7+ p?

2 Answers
Aug 5, 2017

p=-6 or p=7

Explanation:

p^2-35=7+p
=>p^2-p-42=0
=>(p+6)(p-7)=0
=>p=-6 or p=7

Aug 5, 2017

p=7 or p=-6

Explanation:

Bring all terma on one side, p^2-p-35-7=0

p^2-p-42=0

The quadratic formula is p=(-b+-sqrt(b^2-4ac))/(2a)

Here we have: p=(-(-1)+-sqrt((-1)^2-4(1*-42)))/(2*1)

p=(1+-sqrt(1-4(-42)))/2

p=(1+-sqrt(1+168))/2

p=(1+-13)/2

p=14/2=7 or p=-12/2=-6