How do you solve #p- 8p ^ { 1/ 2} + 7= 0#?

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Answer 1 · 2017-11-10T04:46:31

#p = 1, 49#

#p-8sqrtp + 7 =0#

#p - sqrt p -7sqrt p + 7 = 0#

#(sqrtp (sqrt p -1)) - 7(sqrt p - 1) = 0#

#(sqrt p -1)(sqrt p -7) = 0#

#sqrt p = 1, 7#

#p = 1^2 , 7^2#

#p = 1, 49#