How do you solve #\root [ 3] { x + 1} + 5= 3#?

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Answer 1 · 2017-01-22T20:45:06

Subtract 5 from both sides
Cube both sides
Subtract 1 from both sides

Given: #root(3)(x + 1) + 5 = 3#

Subtract 5 from both sides:

#root(3)(x + 1) + 5 -5 = 3 -5#

#root(3)(x + 1) = -2#

Cube both sides:

#(root(3)(x + 1))^3 = (-2)^3#

#x + 1 = -8#

Subtract 1 from both sides:

#x + 1 - 1 = -8-1#

#x = -9#