Question

How do you solve: -sec(-x)cos(-x) ?

Answer 1

`-1`

Explanation:

Knowing that secant and cosine functions are both even:
`f(-x)= f(x)`

`-sec(-x)cos(-x)=`

`-secx*cosx`

Apply reciprocal identity:

`-1/cancelcosx*cancelcosx=`

`-1`