How do you solve #\sqrt { 100} - ( 2+ 4) = 2x#?

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Answer 1 · 2016-11-08T14:06:36

#x# can equal #2# or #-8#.

#sqrt(100) = 10 or -10# therefore two equations need to be solved to find the solution to the problem:

#10 - 6 = 2x#

#4 = 2x#

#4/2 = (2x)/2#

#x = 2#

and

#-10 - 6 = 2x#

#-16 = 2x#

#-16/2 = (2x)/2#

#x = -8#