How do you solve #sqrt{3- 2x} = x#?

1 Answer
Deepak G.
Sep 16, 2016

#x=1#

#x=-3#

Explanation:

#sqrt(3-2x)=x#

or

#3-2x=x^2#

or

#x^2+2x-3=0#

or

#x^2+2x+1-4=0#

or

#(x+1)^2=4#

or

#(x+1)^2=2^2#

or

#x+1=+-2#

or

#x=2-1#

or

#x=1#------------------------Ans #1#

or

#x=-2-1#

or

#x=-3# -----------------------Ans #2#

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