How do you solve #\sqrt { 3m - 18} = \sqrt { 2m - 11}#?

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Answer 1 · 2017-05-28T03:46:20

#m = 7#

Given: #sqrt(3m - 18) = sqrt(2m - 11)#

Square both sides to eliminate the radicals:
#(sqrt(3m - 18))^2 =( sqrt(2m - 11))^2#

#3m - 18 = 2m - 11#

Add #18 # to both sides: #" "3m = 2m + 18 -11#

#3m = 2m + 7#

Subtract #2m# from both sides: #" "3m - 2m = 7#

#m = 7#

CHECK to make sure this answer works:

#sqrt(3*7 - 18) = sqrt(2*7 - 11)#

#sqrt(21 - 18) = sqrt(14 - 11)#

#sqrt(3) = sqrt(3)#