How do you solve #\sqrt { 4+ 4}#?

1 Answer
The Lonely Donut
Feb 12, 2017

# 2sqrt2 #

Explanation:

Since we have # sqrt(4+4) #, we can rewrite it as follows:

# sqrt(4 * 2) #

Now since we have a square root, we have to extract all the squares from within. # 4 # is a square. The square root of # 4 # is # 2 #. So we have:

# 2sqrt2 #

# 2 # is not a square, so it can not be reduced any further. So therefore the answer is

# 2sqrt2 #

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