Question

How do you solve `\sqrt { 4v + 3} = \sqrt { 2v + 15}`?

Answer 1

`v=6`

Explanation:

Square both sides to cancel out the radicals:

`(sqrt(4v+3))^2 = (sqrt(2v+15))^2 ->4v+3=2v+15`

Now we can solve for `v`

`4vcolor(blue)(-2v)cancel(+3color(red)(-3))=cancel(2vcolor(blue)(-2v))+15color(red)(-3)`

`cancel(2v)/cancel2=12/2`

`v=6`