How do you solve#\sqrt { 5t - 1} = - 6#?

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Answer 1 · 2017-03-04T13:19:21

See the entire solution process below:

First, square both sides of the equation to eliminate the radical while keeping the equation balanced:

#(sqrt(5t - 1))^2 = -6^2#

#5t - 1 = 36#

Next, add #color(red)(1)# to each side of the equation to isolate the #t# term while keeping the equation balanced:

#5t - 1 + color(red)(1) = 36 + color(red)(1)#

#5t - 0 = 37#

#5t = 37#

Now, divide each side of the equation by #color(red)(5)# to solve for #t# while keeping the equation balanced:

#(5t)/color(red)(5) = 37/color(red)(5)#

#(color(red)(cancel(color(black)(5)))t)/cancel(color(red)(5)) = 37/5#

#t = 37/5#