How do you solve #\sqrt { b - 7} = 4#?

1 Answer
May 22, 2017

#b = 23#

Explanation:

First, square both sides.

#(sqrt(b-7))^color(blue)(2) = 4^color(blue)(2)#

By doing this, we eliminated the square root. Now add #7# to both sides to isolate the #b# variable.

#b cancel(- 7 color(green)(+7)) = 4^color(blue)(2) color(green)(+7)#

Now simplify the other side by squaring the #4# and then adding #7# to it.

#b = (4*4) + 7#

#b = 16 + 7#

#b = 23#