How do you solve #\sqrt { x ^ { 2} + 49} = x + 5^ { 2}#?

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Answer 1 · 2017-06-23T02:56:28

#x=-11.52#

#sqrt(x^2+49)=x+5^2#

#sqrt(x^2+49)=x+25#

Square both sides

#x^2+49=(x+25)^2#

#x^2+49 = x^2+50x+625#

#50x=49-625 = -576#

#x=(-576)/50 = -11.52#