How do you solve #\sqrt { x + 4} = 2#?

1 Answer
carlosram · Jade
Apr 10, 2018

#x=0#

Explanation:

you square both sides to get 4 then cancel equal terms on both sides of the equation where x=0
then check the solution so #0+4=2 # so divide #4# and #2# and get #2# then get zero so #x=0#.
#(sqrt(x+2))^2=2^2#
#rArr x+4=4#
#rArr x=0#

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