How do you solve #\sqrt { x - 6} = \frac { 1} { 2}#?

Question

478 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-01-30T16:07:50

See a solution process below:

First, square both sides of the equation to eliminate the radical while keeping the equation balanced:

#(sqrt(x - 6))^2 = (1/2)^2#

#x - 6 = 1/4#

Next, add #color(red)(6)# to each side of the equation to solve for #x# while keeping the equation balanced:

#x - 6 + color(red)(6) = 1/4 + color(red)(6)#

#x - 0 = 1/4 + (4/4 xx color(red)(6))#

#x = 1/4 + 24/4#

#x = 25/4#