How do you solve the equation #1/3logx=log8#?
1 Answer
Dec 3, 2016
Explanation:
Using the
#color(blue)"laws of logarithms"#
#color(red)(bar(ul(|color(white)(2/2)color(black)(logx^nhArrnlogx)color(white)(2/2)|)))#
#rArr1/3logx=logx^(1/3)#
#rArrlogx^(1/3)=log8#
#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(logx=logyrArrx=y)color(white)(2/2)|)))#
#rArrx^(1/3)=8#
#color(blue)"cubing both sides"#
#rArrx=8^3=512#
