# How do you solve the equation 4x^2-28x+49=5 by completing the square?

$4 \left({x}^{2} - 7 x + {\left(\frac{7}{2}\right)}^{2}\right) = 5 - 49 + 4 {\left(\frac{7}{2}\right)}^{2}$
$4 {\left(x - \frac{7}{2}\right)}^{2} = 5$
${\left(2 x - 7\right)}^{2} = 5$
$x = \frac{1}{2} \left(7 \pm \sqrt{5}\right)$