Question

How do you solve the equation and identify any extraneous solutions for `24/5=9/(y+2)`?

Answer 1

Two fractions being equal you use the cross-product:

Explanation:

`ifa/b=c/d->a*d=b*c`

`->24*(y+2)=5*9`
`->24y+48=45`
`->24y=-3`

`y=-3/24=-1/8`

There are no extraneous solutions, as the only "condition" is `y!=-2`, as otherwise the numerator of the right fraction `=0`