# How do you solve the equation and identify any extraneous solutions for (r+4)/3=r/5?

$\frac{r + 4}{3} = \frac{r}{5}$
$5 \left(r + 4\right) = 3 r$
$5 r + 20 = 3 r$
$5 r - 3 r = - 20$
$2 r = - 20$
$r = - 10$