How do you solve the equation $x^{2} + 3 x - 2 = 0$ $x^2+3x-2=0$ by graphing?

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Answer 1 · 2017-02-08T07:36:59

$(- 3.562, 0); (0.562, 0)$ $(-3.562, 0); (0.562, 0)$

$x^{2} + 3 x - 2 = 0$ $x^2+3x-2=0$

First find the vertex

$x = \frac{- b}{2 \times a} = \frac{_3}{2 \times 1} = \frac{- 3}{2} = - 1.5$ $x=(-b)/(2xxa)=(_3)/(2xx1)=(-3)/2=-1.5$

Take three values greater than and less than $- 1.5$ $-1.5$

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Plot the points on the graph. Locate the point where it cuts the x-axis.

The points are -

$(- 3.562, 0); (0.562, 0)$ $(-3.562, 0); (0.562, 0)$

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How do you solve the equation x^2+3x-2=0x2+3x−2=0x^2+3x-2=0 by graphing?