How do you solve the equation $x^2+3x-2=0$ by graphing?

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Answer 1 · 2017-02-08T07:36:59

$(-3.562, 0); (0.562, 0)$

$x^2+3x-2=0$

First find the vertex

$x=(-b)/(2xxa)=(_3)/(2xx1)=(-3)/2=-1.5$

Take three values greater than and less than $-1.5$

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Plot the points on the graph. Locate the point where it cuts the x-axis.

The points are -

$(-3.562, 0); (0.562, 0)$

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How do you solve the equation x^2+3x-2=0x^2+3x-2=0 by graphing?