How do you solve the equation #x^2+3x-2=0# by graphing?
1 Answer
Feb 8, 2017
#(-3.562, 0); (0.562, 0)#
Explanation:
#x^2+3x-2=0#
First find the vertex
#x=(-b)/(2xxa)=(_3)/(2xx1)=(-3)/2=-1.5#
Take three values greater than and less than
Plot the points on the graph. Locate the point where it cuts the x-axis.
The points are -
#(-3.562, 0); (0.562, 0)#
