How do you solve the equation #x/4-(3x)/2=-1/2#?

1 Answer
EZ as pi
May 12, 2018

#x=2/5#

Explanation:

If you have an equation which has fractions, you can get rid of the denominators immediately.
Multiply each term by the LCD (in this case it is #4#) and cancel.

#color(blue)(cancel4xx x)/cancel4-color(blue)(cancel4^2xx 3x)/cancel2=color(blue)(cancel4^2xx-1)/cancel2" "# which gives:

#x-6x= -2#

#-5x = -2" "larr div -5#

#(-5x)/(-5) = (-2)/(-5)#

#x = 2/5#

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