How do you solve the exponential equation #4^(2x)=4^(x+2)#?

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Answer 1 · 2017-02-25T17:39:21

#x=2.#

#4^(2x)=4^(x+2).#

#rArr 4^(2x)=4^x*4^2.#

#"Dividing by "4^xne0, 4^(2x)/4^x=4^2.#

#:. 4^(2x-x)=4^2.#

#:. 4^x=4^2.#

#:. x=2.#

This soln. satisfy the given eqn.

The Soln. is #x=2.#