How do you solve the exponential equation $4^(2x)=4^(x+2)$ ?

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Answer 1 · 2017-02-25T17:39:21

$x=2.$

$4^(2x)=4^(x+2).$

$rArr 4^(2x)=4^x*4^2.$

$"Dividing by "4^xne0, 4^(2x)/4^x=4^2.$

$:. 4^(2x-x)=4^2.$

$:. 4^x=4^2.$

$:. x=2.$

This soln. satisfy the given eqn.

The Soln. is $x=2.$

How do you solve the exponential equation 4^(2x)=4^(x+2)4^(2x)=4^(x+2)?