# How do you solve the exponential equation 81^(3-x)=(1/3)^(5x-6)?

$x = - 6$
${81}^{3 - x} = {\left(\frac{1}{3}\right)}^{5 x - 6}$
${\left({3}^{4}\right)}^{3 - x} = {\left({3}^{-} 1\right)}^{5 x - 6}$
${3}^{12 - 4 x} = {3}^{- 5 x + 6}$
$12 - 4 x = - 5 x + 6$
$x = - 6$