Question

How do you solve the exponential equation `81^(3-x)=(1/3)^(5x-6)`?

Answer 1

`x=-6`

Explanation:

`81^(3-x)=(1/3)^(5x-6)`
`(3^4)^(3-x)=(3^-1)^(5x-6)`
`3^(12-4x)=3^(-5x+6)`
`12-4x=-5x+6`
`x=-6`