# How do you solve the following linear system: # 2x+ 3y=-1 , x+4y=1 #?

##### 1 Answer

Easiest way is by substitution.

The solution is

#### Explanation:

Solving a linear system means finding if there's a point

Take the equation

#color(white)=>x+4y=1#

#=>x" " = 1-4y#

Now we know that if there's a point

#color(white)=> 2(" "x" ")+3y=–1#

#=> 2(1-4y) + 3y = –1#

#=>" "2" " -" " 8y " "+ 3y = –1#

#=>" "-5y=–3#

#=>" "y=3/5#

So now we know our point

We can now use this new

#x=1-4y#

#color(white)x = 1 - 4(3/5)#

#color(white)x = 1 - 12/5#

#color(white)x = –7/5#

Thus, our lines cross at the point