How do you solve the following linear system: 2x - 3y = 4 , 3x + y + 2 = 0?

Nov 15, 2015

$\left(- \frac{2}{11} , - \frac{16}{11}\right) \in m a t h \boldsymbol{Q \times Q}$

Explanation:

$y = - 3 x - 2$

$2 x - 3 \left(- 3 x - 2\right) = 4$

$2 x + 9 x = 4 - 6$

$x = - \frac{2}{11}$

$y = - 3 \left(- \frac{2}{11}\right) - 2 = \frac{6 - 22}{11}$